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#3 (permalink) |
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Account Closed
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okay, so I calculated the mass of a sample of NaCl which was 1.0459 (answer via virtual chem lab through my class). They then asked for the moles of NaCl contained in the sample which I calculated to be .0189moles. The next questions says "calculate the moles of each element in NaCl" so my question is do I use the mass of 1.0459 of NaCl or do I calculate the mass of the sample each of them separately (again through virtual chem lab) then divide by their seperate molar masses....i hope that made sense |
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#4 (permalink) | |
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CarolinaHokie
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There IS a more difficult way to do it. You figure out the mass percent of each element (divide molar mass of element by molar mass of NaCl) and then multiply that for each by the mass of the sample and convert the answer to moles. It should give you something close to 0.0189 moles of each. |
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#5 (permalink) | |
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Account Closed
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Molar mass NaCl = 22.9898 + 35.453 = 58.44 g/mol % Na = 22.9898 x 100 / 58.44 = 39.3 If we have 1.02 g of NaCl grams of Na = 1.02 x 39.3 / 100 = 0.401 grams Cl = 1.02 x 60.7 / 100 = 0.619 Moles Na = 0.401 / 22.9898 = 0.0174 Moles Cl = 0.619 / 35.453 = 0.0174 The ratio is 0.0174 : 0.0174 or ( it is the same 1 : 1) and the formula is NaCl this was on yahoo answers lol i did not do this, I was searching for how to do it ETA: what about atoms for each element? same thing? |
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#6 (permalink) | |
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CarolinaHokie
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Thank goodness yahoo has it. I was typing out the math for you. But yeah, that's the math version of how to do it. 0.0174:0.0174 is the same as 1:1. You want the lowest possible ratio.For atoms, you just multiply moles by Avogadro's number. |
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#9 (permalink) |
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Account Closed
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okay...now im confused again lol don't hate me.
Another questions says "calculate the moles of C12H22O11" (sucrose). I know that the mass (via chem lab) is .9565g. When I get the molar mass for each element do I multiply it by their subscript? Like C has a molar mass of 12.011 Do I multiply that by 12 and add it to the others? I suck at explaining things |
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